Given a wind angle of 60°, what is the maximum crosswind factor according to sinus calculation?

The maximum crosswind factor given a wind angle of 60° corresponds to the calculation involving the sine of the wind angle. The crosswind component can be determined using the formula:

[ \text{Crosswind} = \text{Wind Speed} \times \sin(\theta) ]

where ( \theta ) is the angle of the wind relative to the aircraft's flight path. For a wind angle of 60°, the sine value can be calculated as follows:

[ \sin(60°) = \frac{\sqrt{3}}{2} \approx 0.866 ]

This result of approximately 0.866, or 0.86 when rounded appropriately, indicates that the crosswind factor at a wind angle of 60° is maximal at this sine value. Thus, this properly reflects the component of wind that affects the aircraft's lateral movement during takeoff or landing, which is crucial for safe aircraft operations.

Using the sine function makes it clear that as the angle increases to 60°, a significant portion of the wind contributes to the crosswind, leading to an effective crosswind factor close to the calculated value of 0.86. Therefore, B is the correct choice as the maximum crosswind factor